<lecture>
	<step>
		<caption>Introduction</caption>
		<video>./data/expts/ee006/expt6_lecture_intro.flv</video>
		<description><![CDATA[<div class=tdText><p><strong>Operating principle</strong></p><ul><li>Rotating magnetic field created by stator induces e.m.f in rotor</li><li>Current flows through short circuited winding of the rotor</li><li>The current interacts with the rotating flux to produce a torque that causes the motor to rotate in the direction of the rotating magnetic field </li><li>The speed of the rotor is nearly equal to the synchronous speed at no load</li><li>As the load increases, this induction speed drops slightly</li></ul></div>]]></description>
	</step>
	<step>
		<caption>Experiment details</caption>
		<video>./data/expts/ee006/expt6_lecture_details.flv</video>
		<description><![CDATA[<div class=tdText><strong>Instruments Used</strong><ul><li>The total input power measured by two wattmeters (110V, 0 - 15/0-30 HW) </li><li>The stator current and voltage with an A.C. ammeter (0-20A) and an A.C. voltmeter(0-150V)</li><li>The speed is measured by a tachometer (0 - 9999 r.p.m.), and the supply frequency by a frequency meter(45-55Hz)</li><li>3 phase variac used for starting of the motor</li><li>Separately Excited DC Generator for loading the induction motor</li><li>Two d.c. ammeters (0-5A for measuring the field current and 0-20A for measuring armature current), and one d.c voltmeter (0-150V) to measure the voltage in the load</li><li>20A , 110V Loadbox for loading the d.c. generator</li></ul></div>]]></description>
	</step>
	<step>
		<caption>Calculation of performance parameters</caption>
		<video>./data/expts/ee006/expt6_lecture_performance.flv</video>
		<description><![CDATA[<div class=tdText><p><strong>Calculation of Performance Parameters</strong></p><ul><li><strong>Power factor</strong> of induction machine <strong>(cos &theta;) = (W1 + W2) / (v3xVxI )</strong><br> where, <strong>V</strong> and <strong>I</strong> are induction motor input voltage and current,<br>and <strong>W1 + W2</strong> is the Total  power input to the induction motor </li><li><strong>Output of motor (Pout)</strong> = Input of the D.C generator = <strong>Vd.c x Id.c / &eta;d.c.</strong><br>where<strong> &eta;d.c.</strong> = efficiency of the D.C. generator,<br>and	<strong>Vd.c &amp;  Id.c</strong>  are d.c. generator armature voltage and current</li><li><strong>Efficiency of the induction motor (?a.c )</strong>= Output / input = <strong>(Vd.c x Id.c / &eta;d.c.) / (W1 + W2)</strong> </li><li><strong>Torque of induction motor( T )= Pout / (2 x p x nr)</strong> where  <strong>nr</strong> is  the speed of induction motor in r.p.m.</li></ul></div>]]></description>
	</step>
</lecture>
